ABCD
0101
1001
1000
1111
----- zwischensumme
3213
0100
0111
1001
0001
1101
1100
0000
1000
0101
----- zwischensumme
4515
0000
1110
1001
1101
1110
0100
1100
0001
1001
1111
----- zwischensumme
7635
0110
0001
0010
0001
0010
1001
0000
1010
0000
----- zwischensumme
2143
3 2 1 3
4 5 1 5
7 6 3 5
2 1 4 3
-------------
16 14 9 16
absolute wahrscheinlichkeit
H_a = 16
H_b = 14
H_c = 9
H_d = 16
n = 32
h(E) = H/n
h(A) = H_a/n = 16/32 = 0.5
h(B) = H_b/n = 14/32 = 0.4375
h(C) = H_c/n = 9/32 = 0.28125
h(D) = H_d/n = 16/32 = 0.5
man sage ueber die ziffern, welche in welches Ereignis passt
Ereignis E = {ABD} = {H_a = 16, H_b = 14, H_d = 16, n = 32*3}, h(E) = (16+14+16)/(32*3)
Ereignis F = {BD} = {H_b = 14, H_d = 16, n = 32*2}, h(F) = (14+16)/(32*2)
Ereignis G = {AC} = {H_a = 16, H_c = 9, n = 32*2}, h(G) = (16+9)/(32*2)
Ereignis H = {D} = {H_d = 16, n = 32}, h(H) = (16/32)
Ereignis I = {ABC} = {H_a = 16, H_b = 14, H_c = 9, n = 32*3}, h(I) = (16+14+9)/(32*3)
in python3
# (c) david vajda
# wahrscheinlichkeitsausrechnung
# 13/10/25
print ("h(E) = ", (16+14+16)/(32*3))
print ("h(F) = ", (14+16)/(32*2))
print ("h(G) = ", (16+9)/(32*2))
print ("h(H) = ", (16/32))
print ("h(I) = ", (16+14+9)/(32*3))
h(A) = H_a/n = 16/32 = 0.5
h(B) = H_b/n = 14/32 = 0.4375
h(C) = H_c/n = 9/32 = 0.28125
h(D) = H_d/n = 16/32 = 0.5
h(E) = 0.4791666666666667
h(F) = 0.46875
h(G) = 0.390625
h(H) = 0.5
h(I) = 0.40625
h(A) = 0.5
h(B) = 0.4375
h(C) = 0.28125
h(D) = 0.5
h(E) = 0.4791666666666667
h(F) = 0.46875
h(G) = 0.390625
h(H) = 0.5
h(I) = 0.40625
beruehmte tabelle:
in prozent in prozent ist
ist eingetreten nicht eingetreten
relative haeufigkeit relative haeufigkeit
A 0.5 0.5
B 0.4375 0.5625
C 0.28125 0.71875
D 0.5 0.5
E 0.4791666666666667 0.5208333333333333
F 0.46875 0.53125
G 0.390625 0.609375
H 0.5 0.5
I 0.40625 0.59375
0.5
0.5625
0.71875
0.5
0.5208333333333333
0.53125
0.609375
0.5
0.59375
print(1-0.5)
print(1-0.4375)
print(1-0.28125)
print(1-0.5)
print(1-0.4791666666666667)
print(1-0.46875)
print(1-0.390625)
print(1-0.5)
print(1-0.40625)