eulertour

$\begin{displaymath} \begin{array}{c} G=(V,E)\\ V=\{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15\}\\ \end{array}\end{displaymath}$

Jetzt kann man die alle einzelnen rausnehmen, deswegen immer gleich drei

$\begin{displaymath} \begin{array}{c} G=(V,E)\\ V=\{1,2,3,4,5,6,7,8,9,10,11,12,1... ...10),(10,11),(11,12),(11,13)\}\\ Euler_1=((1,2))\\ \end{array}\end{displaymath}$

$\begin{displaymath} \begin{array}{c} G=(V,E)\\ V=\{1,2,3,4,5,6,7,8,9,10,11,12,1... ...),(11,13)\}\\ Euler_1=((1,2),(2,6),(6,3),(3,1))\\ \end{array}\end{displaymath}$

$\begin{displaymath} \begin{array}{c} G=(V,E)\\ V=\{1,2,3,4,5,6,7,8,9,10,11,12,1... ...,5),(5,3))\\ Euler_3=((5,6),(6,7),(7,8),(8,5),)\\ \end{array}\end{displaymath}$

$\begin{displaymath} \begin{array}{c} G=(V,E)\\ V=\{1,2,3,4,5,6,7,8,9,10,11,12,1... ...1,7))\\ Euler_5=((7,12),(12,11),(11,13),(13,7))\\ \end{array}\end{displaymath}$

$\begin{displaymath} \begin{array}{c} G=(V,E)\\ V=\{1,2,3,4,5,6,7,8,9,10,11,12,1... ...9,8),(8,10),\\ (10,11),(11,7)),8),(8,5)),3)),1))\} \end{array}\end{displaymath}$

$\begin{displaymath} \begin{array}{c} G=(V,E)\\ V=\{1,2,3,4,5,6,7,8,9,10,11,12,1... ...8,(9,8),(8,10),\\ (10,11),(11,7),8),(8,5),3),1))\} \end{array}\end{displaymath}$

$\begin{displaymath} \begin{array}{c} G=(V,E)\\ V=\{1,2,3,4,5,6,7,8,9,10,11,12,1... ... = (1,2,6,3,4,5,6,7,12,11,13,7,9,8,10,11,7,8,5,3,1) \end{array}\end{displaymath}$

$Image IMG_9010.tex$

Image graph20250428b1